0=0.01(x)^2+0.04(x)-5

Solution for 0=0.01(x)^2+0.04(x)-5 equation:

0=0.01(x)^2+0.04(x)-5

We move all terms to the left:

0-(0.01(x)^2+0.04(x)-5)=0

We add all the numbers together, and all the variables

-(0.01x^2+0.04x-5)=0

We get rid of parentheses

-0.01x^2-0.04x+5=0

a = -0.01; b = -0.04; c = +5;
Δ = b2-4ac
Δ = -0.042-4·(-0.01)·5
Δ = 0.2016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.04)-\sqrt{0.2016}}{2*-0.01}=\frac{0.04-\sqrt{0.2016}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.04)+\sqrt{0.2016}}{2*-0.01}=\frac{0.04+\sqrt{0.2016}}{-0.02}
$